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3.24x^2+.0843-1.11x=0
We add all the numbers together, and all the variables
3.24x^2-1.11x+0.0843=0
a = 3.24; b = -1.11; c = +0.0843;
Δ = b2-4ac
Δ = -1.112-4·3.24·0.0843
Δ = 0.139572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.11)-\sqrt{0.139572}}{2*3.24}=\frac{1.11-\sqrt{0.139572}}{6.48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.11)+\sqrt{0.139572}}{2*3.24}=\frac{1.11+\sqrt{0.139572}}{6.48} $
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